Two bags of iron ore weigh 180 kg 250 gm and 270 kg 50 gm respectively. How much iron ore (in gm) must be taken out from the first bag and added to the second bag so that weight of the first bag may then be two-third of the second bag?
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 130
Moving ore from one bag to the other does not change the total weight. If the first bag is to be two-thirds of the second, the two bags are in the ratio 2 : 3, so the first bag must hold \(\displaystyle\frac{2}{5}\) of the total.
Total \(=180.250+270.050=450.300\) kg
First bag at the end \(=\displaystyle\frac{2}{5}\times450.300=180.120\) kg
Ore taken out \(=180.250-180.120=0.130\) kg \(=130\) g