Practicing Success
Find the average of squares of first 11 consecutive even numbers. |
184 200 196 150 |
184 |
First 11 consecutive Even numbers are = 2,4,6,−−−−−22
Average of their squares = \(\frac{ (2^2 + 4^2 + 6^2 + ...... 22^2)}{11}\) Average of their squares = \(\frac{ (2^2 ) ( 1^2 + 2^2 + 3^2 + ...... 11^2)}{11}\) Sum of squares of first n natural Number = \(\frac{ n (n + 1) (2n + 1) }{6}\) Average of their squares = \(\frac{4 × 11 × 12 × 23}{11 × 6}\) = 184 |