A thief running at 6 km/hr is chased by a police officer whose speed is 10 km/hr. If the thief is 200 metres ahead of the police officer, then the time required for the police officer to catch the thief will be?
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 3.0 minutes
When two people move in the same direction, the gap between them closes at the difference of their speeds (the relative speed). The police officer has to close the 200 m start of the thief.
Relative speed \(=10-6=4\) km/hr
Gap \(=200\) m \(=0.2\) km
Time \(\displaystyle=\frac{0.2}{4}=0.05\) hour \(=0.05\times60=\) 3 minutes