A random variable X has the following probability distribution
| \(X\) | 2 | 3 | 4 | 5 |
| \(P(X)\) | \(5/k\) | \(7/k\) | \(9/k\) | \(11/k\) |
Then the value of \(k\) is
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 32
The probabilities of a probability distribution add up to 1:
\( \displaystyle \frac{5}{k} + \frac{7}{k} + \frac{9}{k} + \frac{11}{k} = 1 \)
\( \displaystyle \frac{32}{k} = 1 \)
\(k = 32\)