The rate constant of a first-order reaction is 10–2 min–1. The half-life period of the reaction is:
Answer & explanation
Correct answer: option 2
The correct answer is option 2. 69.3 min.
For First order reactions,
\(k =\frac{0.693}{t_{1/2}}\)
Given,
\(k = 10^{−2} \text{ min}^{−1}\)
\(∴ k = \frac{0.693}{t_{1/2}}\)
or, \( t_{1/2} = \frac{0.693}{10^{−2}}\)
or, \(t_{1/2} = 69.3 \text{ min}\)