Practicing Success
A student draws a graph between stopping potential V0(y-axis) and the reciprocal of the wavelength $\left(\frac{1}{\lambda}\right)$ of the incident radiation on the x-axis. What is the slope of the graph? |
$\frac{h}{e}$ $\frac{h c}{e}$ $\frac{h}{c e}$ $\frac{e}{c h}$ |
$\frac{h c}{e}$ |
The correct answer is Option (2) → $\frac{h c}{e}$ |