A student draws a graph between stopping potential V0(y-axis) and the reciprocal of the wavelength $\left(\frac{1}{\lambda}\right)$ of the incident radiation on the x-axis. What is the slope of the graph?
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $\frac{h c}{e}$
$eV_0=\frac{hc}{λ}+\phi$ [Photoelectric equation]
$V_0=\left(\frac{hc}{e}\right)\frac{1}{λ}+\phi$
$⇒y=mx+c$
Hence,
$m=\frac{h c}{e}$