Practicing Success
A manufacturer makes two types of toys A and B. Three machines are needed for this purpose and the time (in minutes) required for each toy on the machines is given below
Each machine is available for a maximum of 6 hours per day. If the profit on each toy of type A is Rs.7.50 and that on each toy of type B is Rs.5, show that 15 toys of type A and 30 of type B should be manufactured in a day to get maximum profit. |
262 264.5 262.5 266.5 |
262.5 |
Let x and y toys of type A and B respectively be manufactured in a day. The given problem can be formulated as follows: Maximise $z=7.5x+5y$......(1) subject to the constraints $2x+y≤60$........(2) $x≤20$........(3) $2x+3y≤120$.........(4) $x,y≥0$..........(5) The feasible region determined by the constraints is as shown The corner points of the feasible region are A(20,0),B(20,20),C(15,30) and D(0,40) The value of z at these corner points are as follows.
The maximum value of z is 262.5 at (15,30) Thus, the manufacturer should manufacture 15 toys of type A and 30 toys of type B to maximize the profit. |