Two ideal diodes are connected to a battery as shown in the circuit. The current supplied by the battery is
Answer & explanation
Correct answer: option 4
Here $D_1$ is in forward bias and $D_2$ is in reverse bias so, $D_1$ will conduct and $D_2$ will not conduct.
Thus, no current will flow through DC.
$I=\frac{V}{R}=\frac{5}{10}=\frac{1}{2}Amp.$