Consider the following hypothesis test:

$H_0: μ = 18$

$H_1:μ≠ 18$,

If a sample of 48 provided a sample mean $\bar x = 17$ and a sample standard deviation $σ=4.5$, then the value of the t-test statistic is:

-1.54

The correct answer is Option (2) → -1.54

Given:

H0: μ = 18, H1: μ ≠ 18

Sample size: n = 48

Sample mean: x̄ = 17

Sample standard deviation: σ = 4.5

t-test statistic formula:

$t = \frac{\bar{x} - \mu}{s / \sqrt{n}}$

Substitute the values:

$t = \frac{17 - 18}{4.5 / \sqrt{48}}$

$t = \frac{-1}{4.5 / 6.9282}$

$t = \frac{-1}{0.649}$

$t \approx -1.54$

Therefore, the t-test statistic value is approximately -1.54