If $a - \frac{12}{a} = 1$, where a > 0, then the value of $a^2 + \frac{16}{a^2}$ is:

15 17 19 11

17

If $a - \frac{12}{a} = 1$ Put the value of a = 4 that will satisfy the given equation. then the value of $a^2 + \frac{16}{a^2}$ is  $a^2 + \frac{16}{a^2}$ = $4^2 + \frac{16}{4^2}$  = 16 + 1 $a^2 + \frac{16}{a^2}$  = 17