Three natural numbers are taken at random from the set A= {x : 1 ≤ x ≤ 100, x ∈ N. then the probability of that AM of the number taken is 25
Answer & explanation
Correct answer: option 3
$x_1+x_2+x_3=75$
coefficient $x^{75}$ in $\left(x^1+x^2+....+x^{100}\right)^3={ }^{74} C_2$
Hence probability $=\frac{{ }^{74} C_2}{{ }^{100} C_3}$.