Kanti and Jiya together can finish a work in 3 days. If Jiya alone can finish the work in 6 days, then in how many days can Kanti alone finish the work?

6 days

Kanti + Jiya = 3 days,

Jiya = 6 days, 

⇒ Kanti + Jiya = 2,    (Efficiency)

⇒ Kanti + 1 = 2,

⇒ Kanti = 1,

⇒ Time required by Kanti to complete the work alone = \(\frac{6}{1}\) = 6 days.     ..(\(\frac{Work}{Efficiency}\) = Time)