If there are 6 girls and 5 boys who sit in a row, then the probability that no two boys sit together is:
Answer & explanation
Correct answer: option 3
⇒ Required probability = $\frac{{^7C}_5×5!×6!}{11!}=\frac{7!\,6!}{11!\,2!}$
If there are 6 girls and 5 boys who sit in a row, then the probability that no two boys sit together is:
Correct answer: option 3
⇒ Required probability = $\frac{{^7C}_5×5!×6!}{11!}=\frac{7!\,6!}{11!\,2!}$