The table givens below presents rainfall (in mm) in two cities on different days of a week.
|
Days |
Rainfall (in mm) |
|
|
City 1 |
City 2 |
|
|
D1 |
82 |
81.6 |
|
D2 |
78 |
79.4 |
|
D3 |
76.2 |
78.3 |
|
D4 |
81.6 |
77.7 |
|
D5 |
79.4 |
84 |
|
D6 |
84 |
83 |
|
D7 |
83.8 |
82 |
The rainfall on day D2 in City 1 is how much percent more than the rainfall on day D4 in City 2?
Answer & explanation
Correct answer: option 1
The rainfall on day D2 in City 1 = 78
The rainfall on day D4 in City 2 = 77.7
Required percentage = \(\frac{78-77.7 }{77.7}\) × 100
= \(\frac{0.3 }{77.7}\) × 100
= \(\frac{100 }{259}\) %