The table givens below presents rainfall (in mm) in two cities on different days of a week.

The rainfall on day D2 in City 1 is how much percent more than the rainfall on day D4 in City 2?

$\frac{100}{259}$

The rainfall on day D2 in City 1 = 78

The rainfall on day D4 in City 2 = 77.7

Required percentage = \(\frac{78-77.7 }{77.7}\) × 100

= \(\frac{0.3 }{77.7}\) × 100

= \(\frac{100 }{259}\) %