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Home Questions TSZ3MNVMAW
Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Determinants

Question:

If $\begin{vmatrix}x^n&x^{n+2}&x^{n+3}\\y^n&
y^{n+2}& y^{n+3}\\z^n&
z^{n+2}& z^{n+3}\end{vmatrix}=(x-y) (y-z) (z-x)(\frac{1}{x}+\frac{1}{y}+\frac{1}{z})$, then n equals

Options:

1

-1

2

-2

Correct Answer:

-1

Explanation:

The degree of the determinant is $n+(n+2)+(n+3)=3n+5$ and the degree of the expression on RHS is 2.

$∴3n+5=2⇒n=-1$

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