A parallel plate capacitor whose capacitance C is 13.0 pF is charged by a battery to a potential difference V = 13.0 V between its plates. What is the potential energy of the capacitor ?

1.098 nJ 2197 pJ 1.98 pJ 2.197 nJ

1.098 nJ

$ U =\frac{1}{2} C V^2 = \frac{1}{2} 13\times 10^{-12} \times 13^2 = 1.098 nJ