A parallel plate capacitor whose capacitance C is 13.0 pF is charged by a battery to a potential difference V = 13.0 V between its plates. What is the potential energy of the capacitor ?
Answer & explanation
Correct answer: option 1
$ U =\frac{1}{2} C V^2 = \frac{1}{2} 13\times 10^{-12} \times 13^2 = 1.098 nJ