For a LPP the feasible solution region is as shown above and the objective function is Min z = 10 x+ 5y Then minimum value of x is : |
80 at (6, 4) 0 at (0, 0) 40 at (0, 8) 50 at (0, 10) |
50 at (0, 10) |
The correct answer is Option (4) → 50 at (0, 10)
Minimum value of Z = 50 at (0, 10) |