CUET Preparation Today
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Electric field due to a ring having charge Q and radius R at a distance x along its axis is E = $\frac{Qx}{4\pi\epsilon_0 (R^2+x^2)^\frac{3}{2}}$ E is maximum at a point where $\frac{dE}{dx}$ = 0 $\Rightarrow x^2+R^2-3x^2$= 0 $\Rightarrow R^2 - 2x^2$ = 0 x = $\frac{R}{\sqrt2}$ |
