Practicing Success
Practicing Success
CUET Preparation Today
Corner points of the feasible region determined by the system of linear constraints are (0, 4), (3, 3), (4, 0). Let $Z= px+ qy (p> 0, q > 0).$ Then the condition on p and q so that minimum of Z occurs at (4, 0) and (3, 3) is : |
$p=3q$ $p=q$ $p=2q$ $p=\frac{q}{2}$ |
$p=3q$ |
