A can do a piece of work alone in 40 days. A and B together can do the same work in 10 days. C is 50% less efficient than B. In how many days can A and C together complete the same work? |
20 days 24 days 16 days 12 days |
16 days |
A = 40 days, A + B = 10 days, ⇒ A + B = 4, (Efficiency) ⇒ 1 + B = 4, ⇒ B = 3, C is 50% less efficient, B : C = 3 : 1.5, ⇒ Time required by A + C to complete the total work = \(\frac{40}{1+1.5}\) = \(\frac{40}{2.5}\) = 16 days, ..(\(\frac{Work}{Efficiency}\) = Time) |