Which of the given values of x and y make the following pair of matrices equal ? $\begin{bmatrix} 3x-2 & y-x\\20 & -2\end{bmatrix}$ and $\begin{bmatrix} 4 & 2\\ 14x-8 & y-6\end{bmatrix}$ |
x and y cannot be found $x=-2, y=-4$ $x=4, y=2$ $x=2, y=4$ |
$x=2, y=4$ |
The correct answer is Option (4) → $x=2, y=4$ comparing corresponding elements $3x-2=4$ $⇒3x=6⇒x=2$ and $-2=y-6$ so $y=4$ $x=2,y=4$ |