A works \(\frac{3}{2}\) as fast as B and B works twice as fast as than C. If together they can finish the task in 24 days, then how many days will A alone finish 75% of the task?

36

                        A   :    B     :    C

 Efficiency:       3    :   2

                                  2     :    1   

                       6    :   4     :    2

                       3    :   2     :    1

Total efficiency = 6

Total work while working together = 6 × 24 = 144

75% of the total work = 144 × 75% = 108

Time taken by A alone = \(\frac{108}{3}\) = 36 days