A works \(\frac{3}{2}\) as fast as B and B works twice as fast as than C. If together they can finish the task in 24 days, then how many days will A alone finish 75% of the task?
Answer & explanation
Correct answer: option 4
A : B : C
Efficiency: 3 : 2
2 : 1
6 : 4 : 2
3 : 2 : 1
Total efficiency = 6
Total work while working together = 6 × 24 = 144
75% of the total work = 144 × 75% = 108
Time taken by A alone = \(\frac{108}{3}\) = 36 days