If x4 + \(\frac{1}{x^4}\) = 14159 , the positive value of x + \(\frac{1}{x}\) is?
Answer & explanation
Correct answer: option 3
If x4 + \(\frac{1}{x^4}\) = a
then x2 + \(\frac{1}{x^2}\) = \(\sqrt {a + 2}\) = b
and x + \(\frac{1}{x}\) = \(\sqrt {b + 2}\)
ATQ,
x4 + \(\frac{1}{x^4}\) = 14159
x2 + \(\frac{1}{x^2}\) = \(\sqrt {14159 + 2}\) = 119
So, x + \(\frac{1}{x}\) = \(\sqrt {119 + 2}\) = 11