Match List-I with List-II List-

CUET Preparation Today

Start Free Mocks

Home Questions TDZ6VGCBQU

Target Exam

CUET

Subject

Chemistry

Chapter

Organic: Aldehydes, Ketones and Carboxylic Acids

Question:

Match List-I with List-II

List-I (Name of Reaction)	List-II (Reagents)
(A) Stephens reaction	(I) $CrO_2Cl_2/CS_2$
(B) Rosenmund reduction	(II) Acyl chloride and anhyd. $AlCl_3$
(C) Etard reaction	(III) $SnCl_2, HCl$
(D) Friedel Craft acylation	(IV) $H_2/Pd-BaSO_4$

Choose the correct answer from the options given below:

Options:

(A)-(III), (B)-(IV), (C)-(II), (D)-(I)

(A)-(II), (B)-(IV), (C)-(III), (D)-(I)

(A)-(III), (B)-(IV), (C)-(I), (D)-(II)

(A)-(IV), (B)-(III), (C)-(I), (D)-(II)

Correct Answer:

(A)-(III), (B)-(IV), (C)-(I), (D)-(II)

Explanation:

The correct answer is Option (3) → (A)-(III), (B)-(IV), (C)-(I), (D)-(II)

List-I (Name of Reaction)	List-II (Reagents)
(A) Stephens reaction	(III) $SnCl_2, HCl$
(B) Rosenmund reduction	(IV) $H_2/Pd-BaSO_4$
(C) Etard reaction	(I) $CrO_2Cl_2/CS_2$
(D) Friedel Craft acylation	(II) Acyl chloride and anhyd. $AlCl_3$

(A) Stephen Reaction: This reaction involves the reduction of nitriles to imines using stannous chloride ($SnCl_2$) and hydrochloric acid ($HCl$), which are then hydrolyzed to form aldehydes.

(B) Rosenmund Reduction: In this process, acyl chlorides are selectively reduced to aldehydes by hydrogenation with hydrogen gas ($H_2$) over a palladium catalyst supported on barium sulfate ($Pd-BaSO_4$).

(C) Etard Reaction: This is an oxidation reaction where the methyl group of an aromatic ring (like toluene) is converted to an aldehyde group using chromyl chloride ($CrO_2Cl_2$) in a solvent like carbon disulfide ($CS_2$).

(D) Friedel-Crafts Acylation: This reaction introduces an acyl group into an aromatic ring by reacting it with an acyl chloride in the presence of anhydrous aluminum chloride ($AlCl_3$), which acts as a Lewis acid catalyst.