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CUET
-- Applied Mathematics - Section B2
Numbers, Quantification and Numerical Applications
What will be solution of (2 to 5) inequalities for real x : $4x- 3≤ 6x+7 $?
[-4, ∞)
[-3, ∞)
[-2, ∞)
[-1, ∞)
The correct answer is option (3) : [-2, ∞)
$4x- 3≤ 6x+7 $
$4x-6x≤7-3$
$-2x≤4$
$x≥2$
∴ Solution is [-2, ∞)
