Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Three-dimensional Geometry

Question:
If the angle \(\theta\) between the line \(\frac{x+1}{1}=\frac{y-1}{2}=\frac{z-2}{2}\) and the plane \(2x-y+\sqrt{\lambda}z=0\) is such that \(\sin \theta=\frac{1}{3}\), then value of \(\lambda\) is
Options:
\(\frac{1}{3}\)
\(\frac{2}{3}\)
\(\frac{4}{3}\)
\(\frac{5}{3}\)
Correct Answer:
\(\frac{5}{3}\)
Explanation:
Apply the formula for angle between line and plane