CUET Preparation Today
| If the angle \(\theta\) between the line \(\frac{x+1}{1}=\frac{y-1}{2}=\frac{z-2}{2}\) and the plane \(2x-y+\sqrt{\lambda}z=0\) is such that \(\sin \theta=\frac{1}{3}\), then value of \(\lambda\) is |
\(\frac{1}{3}\) \(\frac{2}{3}\) \(\frac{4}{3}\) \(\frac{5}{3}\) |
| \(\frac{5}{3}\) |
| Apply the formula for angle between line and plane |
