Width of two slits in Young's double slits experiment are in the ratio 9 : 4. The ratio of the amplitudes of light waves through them would be:
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → 3 : 2
In young's double slit experiment,
$I∝A^2$
$⇒\frac{I_1}{I_2}=\frac{9}{4}$ [Given]
$∴\frac{A_1}{A_2}=\sqrt{\frac{I_1}{I_2}}=\frac{3}{2}$