What is the probability that for S's come consecutively in the word `MISSISSIPPI'? |
$\frac{1}{165}$ $\frac{2}{165}$ $\frac{4}{165}$ none of these |
$\frac{4}{165}$ |
The total number of arrangements of the letters of the word 'MISSISSIPPI' is $\frac{11!}{4!4!2!}$ Considering 4 S's as one letter, there are 8 letters which can be arranged in arrow in ways $\frac{8!}{4!2!}$ ways. ∴ Number of ways in which 4 S's come together = $\frac{8!}{4!2!}$ Hence, required probability $=\frac{8!/4!2!}{11!/4!4!2!}=\frac{8!×4!}{11!}=\frac{4}{165}$ |