In a circle of radius 13 cm, a chord is at a distance of 5 cm from its centre, then length of the chord (in cm) is:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 24
The perpendicular from the centre to a chord bisects the chord. The radius to one end of the chord, the 5 cm perpendicular and half the chord therefore form a right triangle, with the radius as hypotenuse.
Half the chord \(=\sqrt{13^{2}-5^{2}}=\sqrt{169-25}=\sqrt{144}=12\) cm
Length of the chord \(=2\times12=24\) cm