CUET Preparation Today
In the given circuit, the current through the resistor 2kΩ is:
|
2 mA 4 mA 6 mA 1 mA |
6 mA |
In the circuit, Zener diode is used as a voltage regulating device. Therefore, the current in the circuit, $I=\frac{12V}{2kΩ}=6×10^{-3}A=6mA$ |
