If electron, deutron, $\alpha$-particle and proton have same kinetic energy, which one has the largest de-Broglie wavelength.
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → electron
According to De-Broglie
$λ=\frac{h}{P}=\frac{h}{\sqrt{2mKE}}$
$∴λ∝\frac{1}{\sqrt{m}}$
Mass: Electron < Deutron < α-particle
Velocity: Electron > Deutron > α-particle