If electron, deutron, $\alpha$-particle and proton have same kinetic energy, which one has the largest de-Broglie wavelength. |
proton deutron electron $\alpha$-particle |
electron |
The correct answer is Option (3) → electron According to De-Broglie $λ=\frac{h}{P}=\frac{h}{\sqrt{2mKE}}$ $∴λ∝\frac{1}{\sqrt{m}}$ Mass: Electron < Deutron < α-particle Velocity: Electron > Deutron > α-particle |