The value of $\frac{(p - q)^3 + (q - r)^3 + (r - p)^3}{12(p - q) ( q - r) ( r - p)}$, where p ≠ q ≠ r, is equal to :
Answer & explanation
Correct answer: option 3
$\frac{(p - q)^3 + (q - r)^3 + (r - p)^3}{12(p - q) ( q - r) ( r - p)}$
Put p = 2
q = 1
r = 0
$\frac{(2 - 1)^3 + (1 - 0)^3 + (0 - 2)^3}{12(2 - 1) ( 1 - 0) ( 0 - 2)}$
= \(\frac{-6}{-24}\) = \(\frac{1}{4}\)