Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Topic

Ratios

Question:

If p is the third proportional to 3, 9, then what is the fourth proportional to 6, p, 4?

Options:

$\frac{3}{2}$

10

18

$2\sqrt{3}$

Correct Answer:

18

Explanation:

Third proportion to a, b = $\frac{b\; \times\; b}{a}$

Third proportion to 3, 9 = $\frac{9\; \times\; 9}{3}$ 

                                p = 27

 

Fourth proportion to a, b, c = $\frac{b\; \times\;c}{a}$

Fourth proportion to 6, p(27), 4 = $\frac{27\; \times\; 4}{6}$  = 18