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The area of a triangle with vertices A, B, C is given by |
$|\vec{AB} \times \vec{AC}|$ $\frac{1}{2}|\vec{AB} \times \vec{AC}|$ $\frac{1}{4}|\vec{AC} \times \vec{AB}|$ $\frac{1}{8}|\vec{AC} \times \vec{AB}|$ |
$\frac{1}{2}|\vec{AB} \times \vec{AC}|$ |
The correct answer is Option (2) → $\frac{1}{2}|\vec{AB} \times \vec{AC}|$ ## The area of the parallelogram with adjacent sides AB and AC = $|\vec{AB} \times \vec{AC}|$. Hence, the area of the triangle with vertices A, B, C = $\frac{1}{2}|\vec{AB} \times \vec{AC}|$. |
