CUET Preparation Today
If a + b + c = 0, then find the value of \(\frac{a^2}{bc}\) + \(\frac{b^2}{ca}\) + \(\frac{c^2}{ab}\) . |
1 3 5 9 |
3 |
When a + b + c = 0, then a3 + b3 + c3 = 3abc ⇒ \(\frac{a^2}{bc}\) + \(\frac{b^2}{ca}\) + \(\frac{c^2}{ab}\) = \(\frac{a^3 + b^3 + c^3}{abc}\) = \(\frac{3abc}{abc}\) = 3 |
