Practicing Success
Find the area lying above x-axis and included between the circle x2 + y2 = 8x and inside of the parabola y2 = 4x. |
2/3(4 + 3\(\pi \)) 4/3(8 + 3\(\pi \)) 2/3(4 - 3\(\pi \)) 4/3(8 - 3\(\pi \)) |
4/3(8 + 3\(\pi \)) |
Area = \(\int_{0}^{4}d\)x y + \(\int_{4}^{8}d\)x y = 4/3(8 + 3\(\pi \))
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