Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Continuity and Differentiability

Question:

Evaluate $\underset{x→a}{\lim}\frac{x^{3/5}-a^{3/5}}{x^{1/3}-a^{1/3}}$.

Options:

$a^{4/15}$

$\frac{9}{5}a^{4/15}$

$\frac{5}{9}a^{4/15}$

$\frac{1}{9}a^{15/4}$

Correct Answer:

$\frac{9}{5}a^{4/15}$

Explanation:

$\underset{x→a}{\lim}\frac{x^{3/5}-a^{3/5}}{x^{1/3}-a^{1/3}}=\underset{x→a}{\lim}\frac{\frac{x^{3/5}-a^{3/5}}{x-a}}{\frac{x^{1/3}-a^{1/3}}{x-a}}=\underset{x→a}{\lim}\frac{\frac{3}{5}a^{3/5-1}}{\frac{1}{3}a^{1/3-1}}=\frac{9}{5}a^{4/15}[\underset{x→a}{\lim}\frac{x^n-a^n}{x-a}=na^{n-1}]$