Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Relations and Functions

Question:

Find the range of the following function.

$f(x)=\sqrt{2x-3}$

Options:

[0, ∞)

[-∞, ∞)

[-2, 0)

[-2, ∞)

Correct Answer:

[0, ∞)

Explanation:

$f(x)=\sqrt{2x-3}$ is defined if 2x - 3 ≥ 0 or x ≥ 3/2.

∴ x ∈ [2/3, ∞), which is the domain of the function.

$∴ \sqrt{2x-3}≥ 0$

Thus, range is [0, ∞)