The letter series below is made by writing the same group of letters again and again.
B H B Q Z B H B Q Z B H B Q Z B H
If the series is continued in the same way, which letter will be the 64th letter?
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → Q
When a series repeats one group of letters, the letter in any place is found by dividing the place number by the length of the group; the remainder gives the place inside the group.
The repeating group is B H B Q Z, that is 5 letters
\(64 \div 5\) gives quotient 12 and remainder 4 (\(12\times5=60\))
So 12 full groups end at the 60th letter, and the 64th letter is the 4th letter of the group
The 4th letter of B H B Q Z is Q