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An astronomical telescope of ten fold angular magnification has a length of 44 cm. The focal length of the objective is: |
4 cm 40 cm 440 cm 44 cm |
40 cm |
Magnification is $ M = \frac{f_0}{f_e} = 10$ $ f_0 + f_e = 11f_e = 44cm \Rightarrow f_e = 4cm , f_0 = 40cm$ The correct answer is Option (2) → 40 cm |