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If a2 + b2 + \(\frac{1}{a^2}\) + \(\frac{1}{b^2}\) = 4, a ≠ 0, b ≠ 0, then the value of a5 + b5 is? |
8 256 64 2 |
2 |
Put a, b = 1 (let) 12 + 12 + \(\frac{1}{1^2}\) + \(\frac{1}{1^2}\) = 4 (satisfied) Therefore, a5 + b5 = 15 + 15 = 1 + 1 = 2 |
