Practicing Success
Practicing Success
CUET Preparation Today
If $e^y=x^x$, then which of the following is true? |
$y \frac{d^2 y}{d x^2}=1$ $\frac{d^2 y}{d x^2}-y=0$ $\frac{d^2 y}{d x^2}-\frac{d y}{d x}=0$ $y \frac{d^2 y}{d x^2}-\frac{d y}{d x}+1=0$ |
$y \frac{d^2 y}{d x^2}-\frac{d y}{d x}+1=0$ |
The correct answer is Option (4) → $y \frac{d^2 y}{d x^2}-\frac{d y}{d x}+1=0$ |
