Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Geometry

Question:

In ΔABC, AD is a median. If points E, F and G are midpoints of AD, AE and DE, respectively, then what will be the are ΔBFG ?

Options:

$\frac{1}{2}$ (Area ΔABC)

$\frac{1}{8}$ (Area ΔABC)

$\frac{1}{4}$ (Area ΔABC)

$\frac{1}{2}$ (Area ΔBGC)

Correct Answer:

$\frac{1}{4}$ (Area ΔABC)

Explanation:

As points E, F and G are midpoints of AD, AE and DE, respectively

AE = FE = EG = GD

So, They divide the triangle ABD in 4 equal parts.

AD is median . So,

Area of triangle ABD = \(\frac{1}{2}\) × Area of triangle ABC

Area of triangle BFG =  \(\frac{1}{2}\) × ( \(\frac{1}{2}\) × Area of triangle ABC ) 

[ ⇒ AF = FE = EG = GD ]

Area of triangle BFG =  \(\frac{1}{4}\) × Area of triangle ABC