CUET Preparation Today
If A and B are invertible matrices of the same order, then $(AB)^{-1}$ is equal to |
$A^{-1} B^{-1}$ $A^{-1}B$ $B^{-1}A^{-1}$ $AB^{-1}$ |
$B^{-1}A^{-1}$ |
The correct answer is Option (3) → $B^{-1}A^{-1}$ If $A$ and $B$ are invertible matrices of the same order, then: $\left(AB\right)^{-1} = B^{-1} A^{-1}$ |
