If A and B are invertible matrices of the same order, then $(AB)^{-1}$ is equal to
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $B^{-1}A^{-1}$
If $A$ and $B$ are invertible matrices of the same order, then:
$\left(AB\right)^{-1} = B^{-1} A^{-1}$