Mean and Varaince of Binomial distribution $B\left(9,\frac{1}{3}\right)$ are :
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 3, 2
for a binomial distribution,
$E(X)=np$
Variance (X) = $np(1-p)$
$E(X)=9×\frac{1}{3}=3$
$Var(X)=9×3×(1-\frac{1}{3})=2$