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Mean and Varaince of Binomial distribution $B\left(9,\frac{1}{3}\right)$ are : |
3, 2 $3, \sqrt{2}$ $2, 3$ $9,\frac{1}{3}$ |
3, 2 |
The correct answer is Option (1) → 3, 2 for a binomial distribution, $E(X)=np$ Variance (X) = $np(1-p)$ $E(X)=9×\frac{1}{3}=3$ $Var(X)=9×3×(1-\frac{1}{3})=2$ |
