Case : Read the passage and answer the question(s).
A message signal of frequency 10 kHz and peak voltage 10 V is used to modulate a carrier of frequency 1 MHz and peak voltage 20 V.
Determine the lower side band produced.
Answer & explanation
Correct answer: option 3
USB = \(\nu\)c + \(\nu\)m
LSB = \(\nu\)c - \(\nu\)m
\(\nu\)c = 1000 kHz ; \(\nu\)m = 10 kHz
USB = 1010 kHz
LSB = 990 kHz