Case : Read the passage and answer the question(s). A message signal of frequency 10 kHz and peak voltage 10 V is used to modulate a carrier of frequency 1 MHz and peak voltage 20 V.

Determine the lower side band produced.

950 kHz 1010 kHz 990 kHz 1020 kHz

990 kHz

USB = \(\nu\)c + \(\nu\)m LSB = \(\nu\)c - \(\nu\)m \(\nu\)c = 1000 kHz ; \(\nu\)m = 10 kHz USB = 1010 kHz LSB = 990 kHz