A point charge q is placed at P(0, 0, a). The electric flux through CAB due to the electric field of q is Φ. Then

$\Phi=\frac{q}{48 \varepsilon_0}$ $\Phi<\frac{q}{48 \varepsilon_0}$ $\frac{q}{48 \varepsilon_0}<\Phi<\frac{q}{24 \varepsilon_0}$ $\Phi>\frac{q}{24 \varepsilon_0}$

$\Phi<\frac{q}{48 \varepsilon_0}$

The flux is greater in the nearer half of the square OACB.