Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Atoms

Question:

A hydrogen atom (ionisation potential 13.6 eV) makes a transition from third excited state to first excited state. The energy of the photon emitted in the process is

Options:

1.89 eV

2.55 eV

12.09 eV

12.75 eV

Correct Answer:

2.55 eV

Explanation:

Energy released = $13.6\left[\frac{1}{(2)^2}-\frac{1}{(4)^2}\right]$ = 2.55 eV