Practicing Success
A hydrogen atom (ionisation potential 13.6 eV) makes a transition from third excited state to first excited state. The energy of the photon emitted in the process is |
1.89 eV 2.55 eV 12.09 eV 12.75 eV |
2.55 eV |
Energy released = $13.6\left[\frac{1}{(2)^2}-\frac{1}{(4)^2}\right]$ = 2.55 eV |