Practicing Success
If $\int_{-1}^4f(x) dx = 4$ and $\int_2^4(3-f(x)) dx = 7$, the value of $\int_2^{-1}f(x)dx$ is |
2 -3 -5 none of these |
-5 |
$∵\int_{-1}^4f(x) dx = 4$ and $\int_2^4(3-f(x)) dx = 7$ or $\int_4^{-1}f(x)dx=-4$ and $6-\int_2^4f(x)dx=7$ $∴\int_4^{-1}f(x)dx=-4,\int_2^4f(x)dx=-1$ $\int_2^{-1}f(x)dx=\int_2^4f(x)dx+\int_4^{-1}f(x)dx=-1-4=-5$ |