Target Exam

CUET

Subject

Physics

Chapter

Current Electricity

Question:

Choose the correct relation between drift velocity (a) and current density (J) from the following:

Options:

$v_d=Jne$

$v_d=\frac{J}{ne}$

$v_d=\frac{J}{neA}$

$v_d=\frac{J}{ne^2A}$

Correct Answer:

$v_d=\frac{J}{ne}$

Explanation:

The correct answer is Option (2) → $v_d=\frac{J}{ne}$

The current is related to number of charge carries (n) and drift velocity $(v_d)$.

$I=nAev_d$

and,

Current Density $(J) = \frac{nAev_d}{A}$

$J=nev_d$

$⇒v_d=\frac{J}{ne}$